proc argument

RAPID Programming
1

Hi!
Please tell me why it works with num, but does not work with string?

it work:
PROC main
test 1;
test 2;
ENDPROC

PROC test (num x)
IF x = 1 THEN
…
ELSEIF x = 2 THEN
…
ENDIF
ENDPROC

it will be error:

PROC main
test first;
test second;
EMDPROC

PROC test (string x)
IF x = first THEN
…
ELSEIF x = second THEN
…
ENDIF
ENDPROC

2

Don’t use “test” as proc identifier. It looks like it’s reserved.

This syntax seems to work:

PROC abc(string x)
IF x=“first” THEN
ELSEIF x=“second” THEN
ENDIF
ENDPROC

PROC abcd(num x)
IF x=2 THEN
ELSEIF x=3 THEN
ENDIF
ENDPROC

3

Also your syntax when calling:
Test “first”;
To indicate that it is passing a string into the procedure.
And, same as Maxim’s example, you need to have the quotation marks to indicate string data type:
IF x = “first” THEN
UNLESS it is the name of an already declared string data.

4

The quotation marks. Here’s what I missed when working with string. Thanks!

p.s.

I used “test” just for the sample code